4-81z^2=0

Solution for 4-81z^2=0 equation:

4-81z^2=0

a = -81; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-81)·4
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-81}=\frac{-36}{-162}
=2/9
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-81}=\frac{36}{-162}
=-2/9
$